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We obtain the electron mass through this numerical calculus, referred to 1 dm^3 of water equal to 1 kg:
900/100 x 10^-30 x 10^-1 kg = 900/100 (the energies of 10^-2 a.u.m.) having 10^-30 x 10^-1 kg of mass.
900/100 are
the 10^3 particles of matter in 1 a.u.m. divided in the 10^-6 of the matter-antimatter complex.
When these 10^3 are referred to 1 a.u.m., we have 540 particles (how the unitary intensity of the Candle, 540
x 10^12 cycles/s) how the "real matter" 500 (as 1/2 of 10^3) +40 (the
real cycle), summed to 500 (the antimatter) -40 (that negative
reality of the negative time). In this reference to the
a.u.m., the number of the mass precises the 10^-3 unit of the
positive volume containing 10^3 units how the 540/10^6 complexes
particle of 1 a.u.m., that is 0,000540 a.u.m.
But
here we have to refer to the a.u.m. that contains 10^6 complex
particles, expanded in the 6 coordinate lines +x +y +z -x -y -z, while
the kg gravitation happens in only one. So 0,000540, divided by the 6
directions, is 0,00009 in one, while the 10^2 of its section is
0,009.
In this way we have the 9 "third minutes" corresponding to the time of
54/100 of second minutes that goes on simultaneously in the 6
positive-negative directions of the complex space-time-mass. Where the
time advances in 6 directions in the 0,54 s of the time minimum of the
Sidereal Year (365,25 days, 9 prime, 9 second and 0,54 second), the
"third time" is 9 too, because 9 prime and 9 second (with a dimension
6x10 of unitary difference) already both respect the expansion
6 in the cycle 10. On the contrary, 0,54 second minutes, to
respect the same cycle and to count in "third minutes", must divide
itself by 6/100, referring the 6 quantities +0,09x +0,09y +0,09z
-0,09x -0,09y -0,09z = 54/100, to the total 100 "red colored"
quantities of the area 10x10 of the flow. So 54/6 x 10^-2 x 10^2 = 9
"third units" = "third minutes", and 10^-3 = 0,001 how 0,000999 times
0,0000001 is presented in 9 prime, 9 second and 9 third minutes...
in which 0,001 (the 10^-3 unit of the mass 10^3) is all divided
in third minutes how 1 +9 +90 +900 units 10^-3 equal to 10^3
third minutes.
If we divide 0,54 second by 60, to obtain the unitary quantity of the
third minutes corresponding to 0,54 s, by the division 0,54 : 60,
we get 0,009 third minutes whose unit - being it 9/1.000 - is 9/1.000 x 1.000 = 9/1. In this way the "third minute" energy is the unit of the 10^-3 time being 9 times 10^3 of its time 10^-3, where 9/1 is the absolute ratio E/m between the energy and the mass. In
this way 1.000 electrons are as much as 0,54 second minutes (in a.u.m.)
or 9 third minutes in electromagnetic energy measured in kg.
This happens passing from the 0,00054 a.u.m. of a particle, to the 0,009 energies of the cycle of ten 0,0009.
A ideal balance measures as 100 units of pound this mass. The other
900/1.000 of the 1.000 thousandth masses of the electron are green colored and are positioned on the first red
level of the mass, and add all how "pound added in gravitational
energy". In fact the ideal balance doesn't touch this 900 cubes, but
accuses its gravitational energy added to the only 100 known by the
balance, because, caused by this energy added in pound, the balance
measures all the 1.000/1.000 of the particle 10^-1 of the u.a.m.
So, when in the electron mass, we put in 900/100 of energy, we consider
only the green colored quantity of the movement of the red presence of
the masses. In fact this 100 red colored masses are in gravitational
free fall. The situation is this other, in which I show the 100 masses
in the high position.
This
free fall is acted by the electron masses always collocated at distance
10, how a body in free circular orbit that is in eternal fall but is
always collocated to the same distance (1/10 of the a.u.m. cube) because the tangential escape is
always equal to the simultaneous fall, and the result of this eternal
fall is the curvature of the tangent line in a circular form indicating
the free eternal fall. Every turn of the orbit is how the unitary cycle
of this fall that we have divided in 10 units. So the electron (red)
mass, that is always at 1/10 of the 10 distance of the unitary side of
the cubed u.a.m., in its real movement is only the green part that
doesn't appear, but is.
The division 900/100 = 9 reduces to one alone the 100 masses of the red
transversal plane, and the situation is this sequent, that represents a
pure line, because dividing a volume by its transversal plane we have
the only vertical line of the ideal fall of one only particle of
the u.a.m. equal in space at 10^-6 u.a.m. cube, having its side 1 equal
to 10 decimals.
I here show the green 9 decimals of the energy of the electron eternal fall, since it is rotating around its nucleus.
We have these 9 decimal in space equal to 9 unitary energies, and use
the space to count the energy, because 1 energy is the movement of 1
decimal of the space 10 of all the line 1 of the side of the u.a.m.
cube.
Using the space to count the energy of the movement, and using the same
space to count the stopped position 1/10 of the unit of the u.a.m.
cube, this space is a pure line of 9/10 of the u.a.m. side, where the
unitary mass in line is collocated exactly at 10 decimals of distance,
and it is "pound" expressed in kg, the unit of the pound-mass.
To calculate the quantity in kg, we must consider 10^10 u.a.m.
collocated one upon the other, in way that the distance was in space
dimension the same of 1 dm, the space reference of the kg cube.
10 u.a.m. cubes in line form a length of 1 Å (Angstrom, unit of the atomic space) and 10^10 Å are 1 m. So the 1/10 of the Å is the space reference of the u.a.m. and the same 1/10 of the m is the space reference of the kg cube.
So it's evident that 10^10 a.u.m. cube in full linear sequence are the 1 dm of the kg cube.
This kg cube is a volume whose calculus is made in line: 1 dm x 1 dm x 1 dm.
If we put 10^10 u.a.m. sides, at the place of 1 dm we precise the same length of 1 dm in the a.u.m. sides corresponding.
So the dm^3 (equal to 1 kg when is 1 dm^3 of H2O) is 10^10 x 10^10 x 10/10 = 10^30 a.u.m. sides of 10/10 = 1 kg.
To precise the electron quality of 9 energies of the particle that is
1/10 in line of 10/10 of a.u.m., we have to introduce the 9 energies ad
the 10 positions of the side of the 10^3 cube containing the 1.000
particles of the a.u.m., that are 10 in line.
In this way, 10^30 u.a.m. in line, referred to the 10 lines
(energy + mass) of the electron eternal gravitational fall,
becomes the quantity of 9 energies of 10^30 x 10 electrons (1 red + 9 green) = 1 kg.
If 10^31 electrons are equal to 1 kg, 10^-31 kg is 1 electron
having 9 energies. So - since the energy and the mass is the same,
because it is the energy of the mass 1, we don't precise the quality of
the 9, and count 9 masses in movement, only the green colored. and
finally 9 x 10^-31 kg is the energy-mass of 1 electron.
WE CAN ALSO REASON IN THIS OTHER WAY, to have exactly 9 times 10^31 kg.
The mass 1
is the cycle 10 that has lost 9 unitary spaces, to can be amassed in 1
only space.
So 1 mass, in space, is worthed a -9 quantity of space, lost in the amassing.
When we
measure this -9 of space we use 0,109389754 quantities kept away (so subtracted) from -9, so they are negative ones, are
-0,109. The practical result of this subtraction to -9, a negative quantity is: -9 -0,109 = -9,109.
This mass, for us
that consider positive the space, is negative one because it is an
amassing, but we, for the 3th
Dynamic principle "action-reaction", perceive +9,109 (as reaction) the
action -9,109 of the unit mass counted. In fact we measure the
mass through the opposition to the same mass going down, really acted
in up by a balance.
On the contrary the expansion is positive, is
+9 times 1 and the subtraction of the TIE to c subtracts a
quantity to the positive 9, that is reduced to 8,98755...
How is it possible to unify this electron mass 9,109389754
with its 8,98755... expansion, when in a case the tie is added and in
the other it is subtracted, in way that afterwards the numbers are
different ones?
The lack in UNIFICATION is evident one!
E (energy in power) can be equal to two opposite -9 and +9 that summed
annihilate these two opposite works of the amassing and of the
expanding, or can present the Expansion as 9/1 (a 1 expansed 9 times)
and the amassing as the inverse 1/9 (of the 9 amassed in 1). In this
way mc^2 is in number 1/9 x 9/1 = 1 E.
The two oppositions -9 and +9 and 9 and 1/9, are the same thing.
10^+9 and 10^-9 is the absolute case of the index +9 and -9, and are the two inverse 1.000.000.000/1 and 1/1.000.000.000.
Why today the electron appears to have the mass of 9,109389754 x10^-31 kg? This happens how a consequence of our unitary measurement, that put in unitary geometrical TIES that are extraneous to the quantity measured. Here are all this TIES at every dimension referred to the unitary meter:
- 10^-1 is the unit of 10^1. It is the action 1/10 that shows the reaction 10/1 of the unitary cycle of the space. The tie is 1/10, so it is 0,1.
- 10^-2 is the unit of 10^2. It is the transversal area xy = 10x10, of the flow of the mass that flows only in z direction. So we ave the tie 0 at dimension 10^-2, that is 0,00.
- 10^-3 is the unit of 10^3. The time 1/10 is entered in joke and the energy 3x3 of the transversal area xy, now can work in direction z, as the tie 9 that, at the dimension 10^-3 is worthed 0,009.
- 10^-4 is the unit of 10^4. The volume 10^3 is in full real movement and shows the tie 3 on the base of its numerical cycle. At the dimension 10^-4 the tie 3 is 0,0003.
- 10^-5 is the unit of 10^5. This, referred to all the 10^10 Angstrom that form 1 m, is the dimension (10^10)^1/2 of the electric flow. 10^3 x 10^5 counts all the masses electro-magnetics, and are 10^8, whose tie is the 8 on the base of its numerical cycle 10. At the dimension 10^-5 the tie 8 is 0,00008.
- 10^-6 is the unit of 10^6 (all the complex space 10^3 x 10^3). The unit of the mass volume 10^3, multiplied by all the line 10^6, gets the tie 10^9, of the 9 on its decimal base. At the dimension 10^-6 the tie 9 is 0,000009.
- 10^-7 is the unit of 10^7. All the space in 10^10, divided bu the 10^3 unitary masses get the number 10^7, whose tie is the 7 on the base of its numerical cycle 10. At the dimension 10^-7 the tie 7 is 0,0000007.
- 10^-8 is the unit of 10^8, that is all the length electromagnetic having the absolute area 10^2 in 10^10. This precise calculus 10^8 : 10^3 = 10^5 quantifies all the masses electrical of the electron. 5 is the tie on the base of its numerical cycle 10. At the dimension 10^-8 the tie 5 is 0,00000005.
- 10^-9 is the unit of 10^9, =that is all the space runned by the cycle 10, in 10^10 (the usual Angstroms = 1 m). The calculus 10^9 : 10^5 = 10^4, numbers the electrical masses. Th tie is 4 on the base 10 of its numerical cycle. At the dimension 10^-9 the tie 4 is 0,000000004.
0,1
0,00
0,009
0,0003
0,00008
0,000009
0,0000007
0,00000005
0,000000004
==========
0,109389754
The Physicians cannot have more numbers than 9,109389754, because by the cycle 10 can be obtained till 10 decimal numbers. A eleventh decimal number exists, but "isn't yet present" for the reasons told by Planck.
9 is the true, and 0,109389754 is the geometrical tie that if isn't cut away seems a real increment of the mass.
If I put in a geometrical tie, how a lever, I can have more power.
If I put 1 kg on a lever multiplying for 2 the capacity of work... (of work by 1/2), and on another that multiply for 3 this power... I have always 1 kg, and not 2 or 3...
So the Physicians that affirm that the electron mass contains also the geometric contribute similar to a space-temporal lever, are doing an horrible mistake.
It is the same reason of the 365 days 6 hours, 9 prime, 9 second and 54/100 of second of the Sidereal Year. We put in action the BIG GEOMETRY of the space and of the time and the 360 degrees are perceived as 360 +(7+7+7) times 1/4 of presence of 45° +90° +45° (=180° of the plate angle) measured inversely. So 459045 is perceived 540 seconds +9,54 seconds, and are 9 prime, 9 second and 54/100 of seconds that are equal to 1000 electron masses.
Here 7+7+7 is the absolute liberty of the 3 in the 10 cycle, equal to 10 -3 = 7 movements. Since we have reduced 10 of 3, we have to consider 3 times 7, how 7+7+7 = 21. the 1/4 of presence get 21/4 = 5,25, that are 5 days and 1/4 of 24 hours, so they are 6.
Also in the Year, 5,25 days, 9 +9 +54/100 (equal to 9 third minutes), present 999 times 1 how the 999/1 quantity of 10^3 masses.
In substance, the time added to 360 degree, are measured by a geometrical tie, end we, perceiving the geometry whit the necessity to have before the unitary model, afterwards we have also this presence in our count of 360 degrees of turn, as single days.
You say that how the year is really of 365,25 dais and 999 prime, second, and third minutes... in the same way the electron mass is 9,109389754 ? Certainly! The real measurement is this.
But how the degrees of the complete turn are 360, and not 365,25 +999... in the same way, when we need to know the exact quantity, (how the angle turn), we must cut away what instrumentally is necessary to count.
If I have the necessity to have first 1 m, to measure 10 m, I cannot say that the meters are 11, because my instrument is counted.
If I start by 1, to count 10, this 10 is counted at the 11th position.
In the count of the time, we start by the year 0. Only after 1 year we say that the second is the number 1. This system is exact, because cuts away its unit. On the contrary, in Physics, the unit is added to the masses and are subtracted to the expansions, being spacial amassing inverse to spacial expansions and the UNITY OF THE PHYSICS became an UTOPIA.
Isn't yet an UTOPIA when we consider the absolute quantity without the space-time lever! It increases the energy, but is only appearance. I am not stronger if I put on the table 1.000 kg 1 kg at a time. My result of 1.000 kg, put on the table doesn't show my force, but only my astute way to work.